p and q
p 和 q
p 和 q是
p 和Q
Here p and q is probability of success and failure respectively in that node. If p and q are both propositions,? Swapping p and q interchanges F and V while leaving E unchanged. Primes p and q are no longer needed but cannot be disclosed. The primes p and q can be discarded but should not be revealed.
Select two large primes, p and q . Choose two large prime numbers, p and q . Select two very large prime numbers p and q . Both p and q are not indefinitely small.P's and Q 's is entirely different.Both p and q are not indefinitely small.This table has a row for each of the four possible combinations of truth values of p and q . Where p and q are the probability of success and failure on that node. Here p and q is probability of success and failure respectively in that node. 如果p和q 已经在相同的分量之中则不需要采取任何行动. Nothing to do if p and q are already in the same component. 现在假设φ域U包含与端点p和q ,(在从p到q的方向取向)的可微曲线γ。 Now suppose the domain U of φ contains the differentiable curve γ with endpoints p and q ,(oriented in the direction from p to q). . 其中p和q 为K中的元素,使得右手边的多项式x3-px-q没有二重根。 Where p and q are elements of K such that the right hand side polynomial x3- px- q does not have any double roots. 这里的p和q 是任意的两个事件,后一种标示叫作平行移动。 Here p and q are any two events and the last identification is referred to as parallel transport.式中,p和q 分别是代表位置与动量的矩阵,I是单位矩阵。 Where p and q were matrices for location and momentum, and I is the identity matrix. 下面的定义的两个基本的识别器p和q ,我们可以界定两个主要的语法分析组合子,用于选择和顺序:. Following the definitions of two basic recognizers p and q , we can define two major parser combinators for alternative and sequencing:.交叉熵是一个用来比较两个概率分布p和q 的数学工具。 Cross entropy is a mathematical tool for comparing two probability distributions p and q . (p等价于q)意味着,要么(p与q都是真)要么(p和q 都是假). (p iff q) is equiv. to either(p and q are true)or(both p and q are false). 此外,这里要求参数P和Q与p和q 相同,但用于季节部分。 Furthermore, this component requires the parameters P and Q which are the same as p and q , but for the seasonal component.Consideration of all four cases of the possible state combinations for p and q . 设原子命题集合AP={p,q}。p和q 可以模任意可以由Kripke结构建模的系统中的布尔命题。 Let the set of atomic propositions AP={p, q}. p and q can model arbitrary boolean properties of the system that the Kripke structure is modelling. P and Q were out hunting.Destroy all records of p and q . Create two points p and q . Select two very large prime numbers, p and q . If P and Q are two sets,?
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