Примеры использования Exponential time на Английском языке и их переводы на Русский язык
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The exponential time hypothesis implies P≠ NP.
And in space, you encountered an exponential time displacement.
However, if the exponential time hypothesis fails, it would have no implication for the P versus NP problem.
This conjecture(for the k-SAT problem)is known as the exponential time hypothesis.
However, if the strong exponential time hypothesis fails, it would still be possible for sCNF to equal one.
All the best-known algorithms for NP-complete problems like 3SAT etc. take exponential time.
It has also been used successfully for exact exponential time algorithms for independent set.
Therefore, a brute force search for all sequences of Reidemeister moves can detect unknottedness in exponential time.
The exponential time hypothesis, if true, would imply that P≠ NP, but it is a stronger statement.
And with my equipment onboard,I can identify what I believe to be an exponential time contour.
Problems which admit exponential time algorithms on a deterministic Turing machine form the complexity class known as EXP.
Equivalently, any improvement on these running times would falsify the strong exponential time hypothesis.
It has an exponential time complexity with regard to input size, though, which makes it a pseudo-polynomial algorithm.
Conversely, if any of these problems has a subexponential algorithm, then the exponential time hypothesis could be shown to be false.
The strong exponential time hypothesis(SETH) is the assumption that the limiting value s∞ of the sequence of numbers sk equals one.
For example, an algorithm that runs for 2n steps on an input of size n requires superpolynomial time more specifically, exponential time.
Therefore, if the exponential time hypothesis is true, there must be infinitely many values of k for which sk differs from sk+ 1.
Due to the unlimited lookahead capability that the grammar formalism provides,however, the resulting parser could exhibit exponential time performance in the worst case.
The strong exponential time hypothesis leads to tight bounds on the parameterized complexity of several graph problems on graphs of bounded treewidth.
If cliques orindependent sets of logarithmic size could be found in polynomial time, the exponential time hypothesis would be false.
If the exponential time hypothesis is true, then 3-SAT would not have a polynomial time algorithm, and therefore it would follow that P≠ NP.
Therefore, even though finding cliques orindependent sets of such small size is unlikely to be NP-complete, the exponential time hypothesis implies that these problems are non-polynomial.
More generally, the exponential time hypothesis implies that it is not possible to find cliques or independent sets of size k in time nok.
To solve the exact version of SVP under the Euclidean norm, several different approaches are known, which can be split into two classes: algorithms requiring superexponential time( 2 ω( n){\displaystyle 2^{\omega(n)}}) and poly( n){\displaystyle\operatorname{poly}(n)} memory, andalgorithms requiring both exponential time and space( 2 Θ( n){\displaystyle 2^{\Theta(n)}}) in the lattice dimension.
The strong exponential time hypothesis implies that it is not possible to find k-vertex dominating sets more quickly than in time nk- o1.
Some sources define the exponential time hypothesis to be the slightly weaker statement that 3-SAT cannot be solved in time 2on.
The exponential time hypothesis implies that many other problems in the complexity class SNP do not have algorithms whose running time is faster than cn for some constant c.
The exponential time hypothesis also implies that it is not possible to solve the k-SUM problem(given n real numbers, find k of them that add to zero) in time nok.
Therefore, if the strong exponential time hypothesis is true, then there would be no algorithm for general CNF satisfiability that is significantly faster than testing all possible truth assignments.
Therefore, the strong exponential time hypothesis implies either that the trivial protocol for three-party set disjointness is optimal, or that any better protocol requires an exponential amount of computation.