Примери за използване на Are divisible на Английски и техните преводи на Български
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(c) All six numbers are divisible by.
Both of those are divisible by 4. right? both of those are divisible by 4.
Both the numerator and the denominator are divisible by 3.
Both two pi and 360 are divisible by two so lets divide things by two, and if we do that, what do we get?
McGill FIRSTS The discovery that atoms are divisible.
Well, all of these are divisible by x squared.
McGill FIRSTS The discovery that atoms are divisible.
As all even square numbers are divisible by 4, the even numbers of the form 4n+ 2 are not square numbers.
Who can tell me how many of these numbers are divisible by two?
In addition, years that are divisible by 100 but not by 400 are not leap years, as is the case with 1700, 1800, and 1900.
Of the six three-digit integers on the board, which are divisible by four?
If you add two things that are divisible by 3 the whole thing is going to be divisible by 3 So all of this is divisible by 3.
I know that you can tell me how many of these numbers are divisible by two.
Well, these two guys are divisible by y, but this guy isn't, so there is no degree of y that's divisible into all of them.
What are those, again? Numbers greater than 1 that are divisible only by themselves and 1.
The non-zero whole numbers that are divisible into 2 1× 2 definitely works, 1 and 2, but there really aren't any others that are divisible into 2.
Find the sum of all positive two-digit integers that are divisible by each of their digits.
So in this case, it is 8 minus 5, and this will be equal to 3 over 18, which is the answer, but it's not completely simplified,because both 3 and 18 are divisible by 3.
How many positive integer divisors of are divisible by exactly positive integers? 9.
One way is just to kind of look at the multiples of 9 and see if any of them are divisible by 12.
Among them, some percentage p1 are divisible without remainder by 2, percentage p2 are divisible without remainder by 3, percentage p3 are divisible without remainder by 4.
Prove that can be expressed in the form,where are integers and any of them are divisible by 3.
When you have that working, modify your program to print"FizzBuzz" for numbers that are divisible by both 3 and 5(and still print"Fizz" or"Buzz" for numbers divisible by only one of those).
Now the first thing we can do here, just eyeballing each of these terms if we want to simplify it a good bit is all of these terms are divisible by 8.
The twin prime conjecture is all about how andwhen prime numbers- numbers that are divisible only by themselves and 1- appear on the number line.
Prime numbers are those that are divisible only by themselves and 1, but they are also the building blocks of all other numbers which are created by multiplying primes together.
We realize that all of the terms in this big jumble of numbers are divisible by 49 except the final term.
Wo mathematicians have uncovered a simple,previously unnoticed property of prime numbers- those numbers that are divisible only by 1 and themselves.
Find the largest positive integer so that the number of integers in the set which are divisible by 3 is equal to the number of integers which are divisible by 5 or 7(or both).
Starting with the sequence of the natural numbers further sequences are generated as follows: is created from by the following rule: the order of elements remains unchanged,the elements from which are divisible by are increased by 1 and the other elements from remain unchanged.