Примери за използване на Both the numerator на Английски и техните преводи на Български
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We can divide both the numerator and denominator by 4.
So this numerator, let's put the a plus 2's first in both the numerator and the denominator.
Both the numerator and the denominator are divisible by 3.
Well, let's just multiply both the numerator and the denominator here by 10 twice.
Both the numerator and the denominator are divisible by four.
Is divisible by both 10 and 100,so multiply both the numerator and denominator of this character by 10.
If we divide both the numerator and the denominator of both of these expressions by 10 we get 3/100.
But if we wanted to simplify it even more looks like we could divide both the numerator and the denominator by 5.
Let's divide both the numerator and the denominator by four.
And now if I want to reduce this to lowest terms,we can- Let's see, Both the numerator and the denominator are divisible by 5.
So if we divide both the numerator and the denominator by 15, what happens?
And then, if we want to- this isn't in lowest simplified… this isn't in simplified form right here, since both 12 and14 are divisible by 2- lets divide both the numerator and the denominator by 2 and you get 6 over 7.
So let's divide both the numerator and the denominator by 7.
And there's a bunch of ways that we can actually tackle this, butmaybe the easiest is to start with the ratio that they gave us where they gave us both the numerator and the denominator, and then move from there.
So lets divide both the numerator and the denominator by 2.
But we have just successfully decomposed this pretty-- I don't want to say that we necessarily simplified it, because you could say, oh, we only have one expression here,now I have three-- but I have reduced the degree of both the numerators and the denominators.
So let's divide both the numerator and the denominator by 8.
Both the numerator and the denominator are taken from the organization's balancesheet.
To simplify it,we can multiply both the numerator and the denominator by the mean of the x's.
Divide both the numerator and the denominator by two. nine times thirty six over two inches. dividing gives nine times eighteen.
If we had C over the square root of 2,we just multiply both the numerator and the denominator by the same number, right?
If we multiply both the numerator and the denominator of this expression by the complex conjugate of the denominator, then we will have a real number in the denominator.
And if you wanted to compare them directly, you could multiply 3/10 times-- well, both the numerator and the denominator by 10 so you're not changing its value. 10/10 is essentially 1, or it is 1.
If you multiply both the numerator and denominator by negative 1, you could see this written as the mean of the xy's minus the mean of x times the mean of the y's.
We could just cancel these 3's out, or you could imagine this is the same thing as dividing both the numerator and the denominator by 3, or multiplying both the numerator and the denominator by 1/3.
So both of these can never be-- both the numerator and the denominator can never both be positive at the same time because in order for them both to be positive you get an impossible constraint to fill.
So we can divide both the numerator and the denominator by 15.
You multiply both the numerator and the denominator by 10 you will get 5,180.
And we are squaring both the numerator and the denominator.
We have just multiplied both the numerator and the denominator by 100 to shift the decimal over to the right twice.