Примери за използване на Cross product на Английски и техните преводи на Български
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Take the cross product.
Cross product sine of theta.
So that's the cross product.
The cross product is actually almost the opposite.
Thumb is the direction of the cross product.
The cross product cares about the vectors that are perpendicular to each other.
Let's look at the definition of the cross product.
Because when I take the cross product, index finger is the first term of the cross product. .
Middle finger is the second term of the cross product.
So we know that the cross product is the same thing as-- so let's say, what's the magnitude of the force?
Times the distance vector taken-- you take the cross product with the magnetic field.
So the cross product of L with B2 popping out of this page, the net force is going to be in this direction.
On input we have(in calculation we use vector normalization and cross product).
If you differentiate the cross product of"R" and"P" with respect to time, that should equal zero, right?
And I'm almost at my time limit, andso there you have it: the cross product as it is applied to torque.
So when you take the cross product, you're going to see that the net force on this segment of the wire is 0.
And maybe if we have time, we'll, actually figure out some dot and cross products with real vectors.
And that is because torque is defined as the cross product between the radial distance from your axis of rotation and the rotational force being applied.
F is our middle finger, and whichever direction our thumb points in tells us whether or not we are-- the direction of the cross product.
In the next video I will show you how to actually compute dot and cross products when you're given them in their component notation.
Well, look, this cross product, this part of it, the part that just gives us magnitudes, we just calculated that using what we knew before of torques.
And then the other interesting thing is when you take the cross product of two vectors, the result is perpendicular to both of these vectors.
So let's take a look at how I taught you vectors the first time, and then I will show you how that's really the same thing as what we're doing here with the cross product.
But you essentially take the cross product of the velocity and the magnetic field, multiply that times the charge, and then you get the force vector on that particle.
And hopefully, I can track down a vector graphic program.Because I think it will be fun to both calculate the dot and the cross products using the methods I just showed you and then to graph them.
You will see teachers teach the cross product other ways, where they tell you to put your thumb in the direction of the field, and this and that, your palm-- those are all valid.
If a(possibly non-flat) surface S is parameterized by a system of curvilinear coordinates x(s, t), with s andt real variables, then a normal is given by the cross product of the partial derivatives.
And if you do the cross product, or you do the right hand rule on the bottom side, or the behind side, if you could imagine it, you're still going to have a net downward force.
It was that the force of a magnetic field on a moving charged particle is equal to the charge-- that's not what I wanted to do-- is equal to the charge of the particle-- and that's just a scalar quantity-- times the velocity-- the cross product of the velocity of the particle-- with the magnetic field.
This is the definition of a cross product and then we could put-- if we wanted the actual force vector, we can just multiply this times the vector we get using the right-hand rule.