Примери за използване на Numerators на Английски и техните преводи на Български
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Just multiply the numerators.
Here you multiplied the numerators, and you multiplied the denominators.
You multiply all the numerators.
I just multiplied numerators and denominators by three right over here.
And so you multiply all the numerators.
We multiply the numerators, so this is equal to 6 times 1 as our numerator.
And when you multiply fractions,you can just multiply the numerators.
To multiply fractions,simply multiply the numerators and multiply the denominators.
Our denominators are the same,so we can just add the numerators.
And either the numerators are going to be the same, or the denominators are going to be the same.
Practice: Compare fractions with different numerators and denominators.
We can simply look at the numerators to see what portion of those 30 the fraction represents.
And lets see is we can figure out a pattern for the numerators here.
The total sum of the numerators- 37 и the total sum of the denominators- 67 give a new fraction- 37/67.
So you just multiply 1/2 times 3/4, and this is equal to-- you multiply the numerators.
So we have onefourth plus two fourths, so we know that we just add the numerators, three, and the denominators are the same, three fourths.
This is going to be equal to-- in the numerator,we just multiply the numerators.
We just added the 2 terms, got 0/0, took derivatives of the numerators and the denominators 2 times in a row to eventually get our limit.
The easiest way is if they had the same denominator,you could just compare the numerators.
This is equal to, if we just multiplied the numerators, a squared minus 4 times a plus 1, all of that over-- multiply the denominators-- a squared minus 1 times a plus 2.
The fractions should all be made to have a common denominator with different numerators.
The degree is 2,so the degree of its numerators is going to be 1, and since its degree is 1 it could still have a constant term, which is a 0-degree term, so you get bx plus c.
And now we can just multiply the numerator and multiply the denominator-- or multiply the numerators.
Well the denominators are the same,so the numerators have to equal each other, so we have-- I will rewrite it-- 10x squared plus 12x plus 20 is equal to a times x squared plus 2x plus 4 plus bx plus c, all of that times x minus 2.
To write the elements of as fractions in lowest terms,how many different numerators are required?
Then the"curious property" is that each member of the sequence is equal to the rational whose numerator is the sum of the numerators of the fractions on either side, and whose denominator is the sum of the denominators of the fractions on either side.
Now, notice that the numbers divisible by have now been counted,though they provide different numerators.
We have a 4 in the denominator, that will eventually be in the denominator,so let's divide our eventual numerators and our eventual denominators both by 4.
So what we could do is we can find a common denominator for both of them and convert both of these fractionsto have the same denominator and then compare the numerators.
And like we have done in every problem so far, the denominators are the same,so we can just set the numerators equal to each other and try to solve for A, B, and C.