Examples of using Second derivative in English and their translations into Hebrew
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Show second derivative.
Now we have to get the second derivative.
The second derivative would be 2A.
This was the second derivative.
The second derivative is equal to what?
And what do they tell us about the second derivative?
Well a second derivative would be 2Ax plus B.
So we will have A times the second derivative of this thing.
When the second derivative is positive, the point is a minimum.
Between point 1 and point 2 a parabola with second derivative= 4.
So if we have the equation the second derivative of y plus y is equal to sine of 2t.
That means that we're now going to start involving the second derivative.
The second derivative becomes negative, so we enter a point that is concave downwards.
If I just distribute this out I get the second derivative, which is this.
So the second derivative-- we're going to have to do the product rule twice-- derivative of this first expression.
Or another way of doing it, it's like taking the second derivative of the position function, right?
And that is, if I had the Laplace Transform,let's say I want to take the Laplace Transform of the second derivative of y.
That means that A times the second derivative of h plus B times h prime plus C times h is equal to 0.
And we used this property in the last couple ofvideos to actually figure out the Laplace Transform of the second derivative.
A times the second derivative plus B times the first derivative plus C times the function is equal to g of x.
Let's do another problem where wegraph a function based on the properties of its derivatives and second derivative.
But anyway, I essentially-- to get this, I just substituted the second derivative, the first derivative, and g back into the differential equation.
If the second derivative is positive, the point is a minimum, if the second derivative is negative, then the point is a maximum.
As you see,the approximation between two points on a given function gets worse with the second derivative of the function that is approximated.
And we get the Laplace transform of the second derivative is equal to s squared times the Laplace transform of our function, f of t, minus s times f of 0, minus f prime of 0.
So the second derivative, that's r squared times e to the rx, plus 5 times the first derivative, so that's 5re to the rx, plus 6 times our function-- 6 times e to the rx is equal to 0.
So we need to find a y where 1 times its second derivative, plus 5 times its first derivative, plus 6 times itself, is equal to 0.
A-- so the second derivative of the sum of those two functions is going to be the second derivative of both of them summed up-- plus B times the first derivative of the sum plus C times the sum of the functions.
And that also means that the second derivative at any point is equal to the function of that value or the third derivative, or the infinite derivative, and that never ceases to amaze me.
The Laplace Transform of the second derivative is s squared times the Laplace Transform of the function, which we write as capital Y of s, minus this, minus 2s-- they gave us that initial condition-- and then minus 1.