Examples of using Multiply both sides in English and their translations into Malay
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Ecclesiastic
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Computer
Multiply both sides by- 1.
If we want to solve this, we can multiply both sides by 4.
Multiply both sides by 10.
I don't like these one halves lying around, so let's multiply both sides, this equation, by 2.
Next multiply both sides by -1.
If we were multiplying by a negative number,we would have to swap the inequality. So we can multiply both sides of this by 2/3.
So we multiply both sides by 8.
And if we wanted to solve for x, and I will just do that, because it will be convenient later, we can multiply both sides of this equation by A and you get A sine of beta is equal to x.
So you multiply both sides times 2 fifths.
So the best way to just have aC on the left-hand side is we can multiply both sides of this inequality by the inverse of -5 or by-(1/5).
And then multiply both sides of this equation by 10.
Tangent of 40 degrees is 0.84. So we get0.84 is equal to h/20. So we can multiply both sides of that by 20 and we get h is equal to 20 times 0.84.
We can multiply both sides of this equation by x plus two over one.
If I start with 3x is equal to 15, you might say hey, Sal, instead of dividing by 3, I could also get rid of this 3,I could just be left with an x if I multiply both sides of this equation by 1/3.
See, if you multiply both sides of that times the slope.
Now let's distribute the b, so 30 is equal to b squared over 2- be careful. b/2 times b is just b squared over 2- and then b/2 times -4 is -2b now just to get rid of this fraction here,let's multiply both sides of the equation by two.
Multiply both sides by 1/2 or divide both sides by 2.
So we could then solve for x, multiply both sides but 7 and you get x is equal to 14 over 5.
Multiply both sides by B and you get B sine of alpha is equal to x.
So we get minus 9 plus 8 cosine of 18t is equal to minus h,and then multiply both sides by negative 1, and then you get 9-- positive 9, right-- minus 8 cosine of 18t is equals to h, or h is equal to 9 minus 8 cosine of 18t.
So if I multiply both sides of this equation by 1/3 that should also work.
Now to isolate the z we can just divide both sides of this inequality by negative 3 butremember when you divide or multiply both sides of an inequality by a negative number, you have to swap the inequality. So we can write negative 3z.
And then we can multiply both sides by dx, and you get du is equal to minus sin of x dx.
Let's multiply both sides of this by a negative 1, and you get minus du is equal to sin of x dx.
And then you could multiply both sides' times the reciprocal of 5 halves.
We can multiply both sides of this by the diameter and we could say that the circumference is equal to pi times the diameter.
Now, to isolate the y, you can either multiply both sides by negative 1/12 or you could say let's just divide both sides by negative 12.
Let's see, if we multiply both sides of this equation by 2/9, what do we get? If you multiply both sides by 2/9, it's a positive number, so we don't have to do anything to the inequality. These cancel out, and you get x is less than 3 times 2/9.
So if you multiply both sides by 7, you get 2x plus 9 times 7 is 63, is greater than 5.
Multiplying both sides by V.

