Examples of using The lambda in English and their translations into Polish
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Colloquial
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Official
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Medicine
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Ecclesiastic
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Ecclesiastic
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Financial
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Official/political
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Programming
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Computer
We have the Lambda Sigs.
The lambda parameter must be positive.
And there's the Lambda tattoo.
The lambda and number parameters must be positive.
I have been studying at the Lambda house.
People also translate
The lambda sigs are having a bonfire up the canyon.
He didn't play ball with the Lambda Sig.
Winner for the Lambda Literary Award.
Ready to get sluttered by the Lambda Sigs?
The Lambda Sigs are the second hottest house on campus.
Up to 14 days for the Lambda products.
We're keeping the Lambda Nus up here, and the Kappa Gamma Kappas are in holding on two.
So how important is athletics to the Lambda Sigs?
Which means the Lambda Sigs are the winners of ZBZ fest.
I can't wait for our pref party with the Lambda Sigs.
That is y is equal to e to the lambda x, times some constant-- I will call it c3.
In the lambda calculus, a term is in beta normal form if no beta reduction is possible.
Let the Omega Chis and the Lambda Sigs kiss his ass.
I'm Panos Patakos,president of the Lambda Omega Omega fraternity.
On February 1, the Lambda Association, a Warsaw-based NGO, opened the first shelter for homeless LGBTI persons.
I can't believe you're actually gonna clean the Lambda Sigs'bathroom.
The lambda expression is itself unnamed, but the function acquires a name by being assigned to identifier a.
If the user wishes to take a lambda function as a parameter, the parameter type must be a template type, or they must create a std:: function ora similar object to capture the lambda value.
It is my pleasure to welcome you to the Lambda Mu chapter of Kappa Kappa.
Attempting to use any external variables in the lambda is an error.//x is captured by value, y is captured by reference//any external variable is implicitly captured by reference if used//any external variable is implicitly captured by value if used//x is explicitly captured by value.
So we can rewrite that as y is equal to e to the lambda x times-- let's do the first one-- c1.
Moreover, an exhaust gas analyser calculates the lambda value from the volume fractions of the components of the exhaust gas.
We learned that if the roots of our characteristic equation are r is equal to lambda plus or minus mu i,that the general solution for our differential equation is y is equal to e to the lambda x times c1 with some constant cosine of mu x, plus c2 times sine of mu x.