Examples of using Linear equation in English and their translations into Thai
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Colloquial
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Ecclesiastic
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Ecclesiastic
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Computer
So what were linear equations?
Linear equations, x and y.
But let's go back to linear equations.
It's a linear equation, and the highest degree here is 1.
Well, this is just a straight up linear equation.
Linear equations. and you might be saying: well you know, this is an equation. .
Because this is such a simple linear equation to solve.
And if you're doing this in you Algebra 1 or your Algebra 2 class you're probably using it to represent linear equations.
I told you to solve all the linear equations by today!
This magenta line shows us all the x and y values that satisfy this first linear equation.
So it's not like when you're doing a linear equation you could multiply 1/a on this side.
That's how we would do it in a traditional simple, linear equation.
So just to tie this altogether with linear equations and graphs of them, let's graph this relation.
Find the missing value to make the table represent a linear equation.
And if I can go from that to just the standard linear equation definition, ax plus by plus cz is equal to 0.
And I have used it before, when we were just doing linear equations.
So you may or may not already know that any linear equation can be written in the form y is equal to mx plus b.
Welcome to the presentation on level four linear equations.
And so that tells us that these two linear equations intersect at the point x is equal to 1, y is equal to 2.
Now I can go back from this world, back to my linear equations.
Linear equation problem, then the linear equation problem would be translated a times x plus b times y is equal to e.
Just so you remember, this is just another representation of these actual linear equations.
But let me put it back to my system of linear equations, to see what our result is.
So the easier one to solve is this top equation because it's a linear equation.
And so where essentially this equation, this is a linear equation that is trying to solve this problem.
And the temptation here is really to kind of try to solve it the way you do a linear equation.
So, if you're given a linear equation, and if you know the inverse of this matrix, to solve for x and y, we just have to multiply this number times the inverse.
And this works every time for second order homogeneous constant coefficient linear equations.
And like the first video, where I talked about reduced row echelon form, and solving systems of linear equations using augmented matrices, at least my gut feeling says.
Now using this information, how can we get to this type of an expression, just this linear equation of x, y and z?