Examples of using Second entry in English and their translations into Thai
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Colloquial
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Ecclesiastic
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Ecclesiastic
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Computer
And then the second entry's going to be c times k1 plus d times 0.
Let me replace this guy with that guy, with the first entry minus the second entry.
I found second entry under the name of that woman.- Edith Brennan?
So it will be ad minus bc times your first entry in your column vector minus b times your second entry.
The second entry becomes the second entry plus the first entry. .
If we call this the x-dimension, if the first entry corresponds to our x-dimension, the second entry corresponds to our y-dimension.
But when you look at this second entry you think that c would have to be equal to 1/2.
This is going to be A1 times this first entry right here,times x1, plus A2 times a second entry, plus A3 times a third entry. .
And then the second entry is going to be the dot product of this row vector with this column.
For any free variable, if this free variable represents a second entry, we're going to have a 1 in the second entry here.
The second entry is going to be the second row of A essentially dotted with this vector right there, so it's going to be equal to 0, minus 2, and 1, dotted with 1, 2, 3.
The first entry's going to be a times k1 plus b times k2. a times k1 plus b times k2, and the second entry's going to be c times k1 plus d times k2.
And then a 0 for the second entry for all of the other vectors associated with the other free variables.
He has a 1 in the second term because he corresponds to the free variable x2,which is the second entry, so we just throw a 1 here.
T of x1 x2 is equal to-- let's say the first entry is x1 plus 3x2, the second entry is 5x2 minus x1, and let's say the third entry is 4x1 plus x2.
I'm going to have one row times this and that's going to be the first entry, then this row times, that's the second entry, and then the third row.
So this adjacent side, which we said is going to be our new second component, our second entry, is going to be equal to cosine of theta, right?
And then in my second row are my second entries in my column vectors, 0 divided by anything is 0.
Now I just want to make that clear because I did all of the second entries of all of the column vectors at once because we all were essentially performing the same row operation, so that just helped me simplify at least my thinking a little bit.
We're a minute and 45 seconds from entry.