Примери коришћења Both of these equations на Енглеском и њихови преводи на Српски
{-}
-
Colloquial
-
Ecclesiastic
-
Computer
-
Latin
-
Cyrillic
So this x and y satisfy both of these equations.
Which means that there is no point on the coordinate plane on the x-,y-coordinate plane that satisfies both of these equations.
And actually, I will do both of these equations at the same time.
So we're looking for x's andy's that satisfy both of these equations.
If you were to graph both of these equations, they would intersect at the point negative 5 comma 7.
And we want to find an x andy value that satisfies both of these equations.
So what does it mean for both of these equations to have no solution?
So when you say, well, what are the x's andy's that satisfy both of these equations?
So in order to satisfy both of these equations, x has to satisfy this constraint right here. So I can substitute this back in for x.
Remember, we're just looking for values that satisfy both of these equations.
Well for an X-Y pair that satisfies both of these equations, that's what a solution would be, for that X-Y pair, X plus 2y is equal to negative one.
So we figured out the x value for the x and y pair that satisfy both of these equations.
So it satisfies both of these equations and now we can type it in to verify that we got it right, although, we know that we did, so x=2 and y=-1.
A solution to a system of equations is an x andy value that satisfy both of these equations.
Now, if there were such an x andy value that satisfied both of these equations, then that x and y value would have to lie on both of these graphs.
Any point on this line, which is both of those lines,will satisfy both of these equations.
And the answer is, we can multiply both of these equations in such a way that maybe we can get one of these terms to cancel out with one of the others.
So you're going to have infinitely many solutions if essentially both of these equations are describing the same line.
And so what I need to do is massage one or both of these equations in a way that these guys have the same coefficients, or their coefficients are the negatives of each other, so that when I add the left-hand sides, they're going to eliminate each other.
If you think of it graphically,this would be the intersection of the lines that represent the solution sets to both of these equations.
So his first equation is actually unchanged from the teacher's equation, is unchanged from the teacher's equation, so any solution that meets both of these equations is for sure gonna meet this top equation because it's literally the same as the top equation of the teacher, so that works out.
And I encourage you to find the equations of both of these lines and graph both of these lines, and verify for yourself that they are indeed parallel.
If we add 150 to both sides of these equations, if you add 150-- and we can actually do both of them simultaneously-- let's add 150 on this side, too, what do we get?
And I encourage you to find the equations-- I already got the slopes for you-- but find the equations of both of these lines, plot them, and verify for yourself that they are perpendicular.