Examples of using First derivative in English and their translations into Hebrew
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Show first derivative.
I'm going to add minus 3 times the first derivative to that.
So the first derivative of this y prime is equal to A cosine of x.
Plus 4 times the first derivative.
The first derivative to be added will be the Taycan Cross Turismo at the end of next year.
So that's the information to tell us about the first derivative.
So what is the first derivative of it, first of all.
And, maybe at a given value of x, what the first derivative is.
The first derivative of this quadratic-- but any quadratic can be written like this-- is 2ax plus b.
If this box is checked, the first derivative will be plotted, too.
Now, we have to do the Laplace transform of 2 times the first derivative.
A times the second derivative plus B times the first derivative plus C times the function is equal to g of x.
So our first derivative is y prime is equal to-- let's see c1-- 1/2 plus c2-- so it's-- well I will write this first-- it's equal to 2 over 2.
We have second derivative of y, plus 4 times the first derivative, plus 4y is equal to 0.
So I can just rewrite that as A-- so now A is not a function anymore, it's just a number-- A times the second derivative of y, with respect to x,plus B times the first derivative.
The second derivative of y minus 3 times the first derivative y minus 4 times the function.
The first derivative Valyrian language to be featured in the series was Astapori Valyrian, a variety from the city of Astapor in Slaver 's Bay. It appeared in the third-season premiere episode" Valar Dohaeris". Peterson created the Astapori dialogue by first writing the text in High Valyrian, then applying a series of regular grammar and sound changes to simulate the changes in natural languages over a long period of time.
We know the solution to the second derivative minus 3 times the first derivative minus 4y.
That's just g prime prime, plus h prime prime,plus B times-- the first derivative of this thing-- g prime plus h prime, plus C times-- this function-- g plus h.
So let's say I had thedifferential equation y prime prime plus the first derivative plus y is equal to 0.
And we get A-- let's take this one; let's take all the g terms-- A times the second derivative of g,plus B times the first derivative, plus C times g-- that's these three terms-- plus A times the second derivative of h, plus B times the first derivative, plus C times h.
A-- so the second derivative of the sum of those two functions is going to be the second derivative of both of them summed up--plus B times the first derivative of the sum plus C times the sum of the functions.
So let's say our differentialequation is the second derivative of y minus the first derivative plus 0.25-- that's what's written here-- 0.25y is equal to 0.
And you have to say, well, if I want some function where I take a second derivative and add that orsubtracted some multiple of its first derivative minus some multiple of the function, I get e to the 2x.
But anyway, I essentially-- to get this, I just substituted the second derivative, the first derivative, and g back into the differential equation.
So we need to find a y where 1 times its second derivative, plus 5 times its first derivative, plus 6 times itself, is equal to 0.
So the derivative of the first term.
So let's just figure out the derivative of this first.
So first we take the derivative of this first term, and once again we learned in the last presentation the most amazing fact, one of the most amazing facts in the universe that the derivative of e to the x is what?
So, product rule, derivative of the first, v prime times the second expression, e to the minus 2x, plus the first function, or expression, times the derivative of the second.