Examples of using Binary operation in English and their translations into Indonesian
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Computer
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Colloquial
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Ecclesiastic
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Ecclesiastic
Elemental binary operation.
Rings and fields- structures with two binary operations.
However the binary operation might not be associative.
Invalid operands in binary operation.
A binary operation f on a set S may be viewed as a ternary relation on S, that is, the set of triples(a, b, f(a, b)) in S× S× S for all a and b in S.
Non-register as LHS of binary operation.
On the set of natural numbers N, the binary operation exponentiation, f(a, b) ab, is not commutative since, in general, ab≠ ba and is also not associative since f(f(a, b), c)≠ fa, fb, c.
A quasi-group satisfies a requirement that any element can be turned into any other by either a unique left-multiplication or right-multiplication;however the binary operation might not be associative.
This property is shared by most binary operations, but not subtraction or division.
A binary operation, ab, depends on the ordered pair(a, b) and so(ab)c(where the parentheses here mean first operate on the ordered pair(a, b) and then operate on the result of that using the ordered pair((ab), c)) depends in general on the ordered pair(a, b), c.
A group is a combination of a set S and a binary operation'*' with the following properties.
A binary operation f on a set S may be viewed as a ternary relation on S, that is, the set of triples(a, b, f(a, b)) in S× S× S for all a and b in S. An external binary operation is a binary function from K× S to S. This differs from a binary operation on a set in the sense in that K need not be S; its elements come from outside.
On the set of real numbers R,{{ math| size=100%| 1=f( a, b)= a+ b}}is a binary operation since the sum of two real numbers is a real number.
An external binary operation may alternatively be viewed as an action; K is acting on S. The dot product of two vectors maps from S× S to K, where K is a field and S is a vector space over K. It depends on authors whether it is considered as a binary operation. .
So, the statement"a group is a combination of a set S and a binary operation'*'" is already saying that the operation is closed.
More precisely, a binary operation on a set S is a map which sends elements of the Cartesian product S× S to S: f: S× S→ S.{\displaystyle\, f\colon S\times S\rightarrow S.} Because the result of performing the operation on a pair of elements of S is again an element of S, the operation is called a closed binary operation on S or sometimes expressed as having the property of closure.
On the set of real numbers R, f(a,b)= a+ b is a binary operation since the sum of two real numbers is a real number.
Because the result of performing the operation on a pair of elements of S is again an element of S,the operation is called a closed binary operation on S(or sometimes expressed as having the property of closure).
Note that the dot product of two vectors is not a binary operation, external or otherwise, as it maps from S× S to K, where K is a field and S is a vector space over K.
For a given set C, let S be the set of all functions h: C→ C. Define f: S× S→ S by f(h1, h2)(c) h1∘ h2( c) h1( h2( c)) for all c∈ C, the composition of the two functions h1 andh2 in S. Then f is a binary operation since the composition of the two functions is another function on the set C that is, a member of S.
Question 3: Note that the of two vectors is not a binary operation, external or otherwise, as it maps from S× S to K, where K is a field and S is a vector space over K.
On the set M(2,R) of 2× 2 matrices with real entries, f(A,B)= AB is a binary operation since the product of two such matrices is a 2× 2 matrix.
A group is a combination of a set S and a single binary operation∗, defined in any way you choose, but with the following properties: An identity element e exists, such that for every member a of S, e∗ a and a∗ e are both identical to a.
On the set M(2,R) of 2× 2 matrices with real entries, f(A, B)A+ B is a binary operation since the sum of two such matrices is another 2× 2 matrix.
By changing the set N to the set of integers Z', this binary operation becomes a partial binary operation since it is now undefined when{{math|size=100%|1=a= 0}} and b is any negative integer.
On the set M(2,R) of 2× 2 matrices with real entries, f(A, B)AB is a binary operation since the product of two such matrices is another 2× 2 matrix.
Suppose there are equivalence operations on these sets(whichalso need not be different), and the binary operation preserves equivalence, i.e., the operation when applied to equivalent operands gives equivalent results, or a~ b and c~ d imply that ac~ bd.