Examples of using This angle in English and their translations into Malay
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Colloquial
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Ecclesiastic
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Computer
Let's call this angle y.
This Angle Drilling Machine.
Especially from this angle.
What is this angle going to be?
Then say it from this angle.
This angle and this angle are corresponding.
So let's go, we have to go on either side of this angle right over here.
Now if this angle is theta, what's this angle going to be?
For example, these two triangles, if I were tell you that this angle-- and this is how they do it in class.
We have one angle and triangle A, E, C that is congruent to another angle in B, D,C and then we have this angle that is obviously congruent to itself, That's in both triangles.
And we see that this angle and this angle, this angle has a measure of 4x,this angle has a measure of 2x.
So a radian-- one radian-- is the angle that subtends an arc that's the length of the radius. So the length ofthis is also r. And this angle is one radian. i think that's messy.
Well if this angle up here is congruent--(And we have constructed it soit is congruent.) the angle corresponding to theta is also going to be theta, And this angle right over here is also going to be 90- theta.
But let's do another angle, let's do another angle up here,and let's call this angle- I don't know, I will think of something, a random Greek letter. So let's say it's psi. It's, I know, a little bit bizarre.
Now we have other words when our two angles add up to other things, so let's say for example I have one angle over here, that is, I will just make up,let's just call this angle, let me just put some letters here to specify,'X','Y' and'Z'.
Note: any further increase on this angle of incidence would cause the refracted ray to turn back into the original medium where it would abide by the laws of reflection(i.e., it would be totally internally reflected.).
Actually, regardless of whether the lines are parallel,if I just take any line and I have something intersecting, if this angle is 50 and whatever this angle would be, they would have to add up to 180 degrees.
We also know that this angle here is going to be equal to the angle that is it's vertical angle or the angle that is opposite the intersection so it's going to be equal to that.
For a simple(non-self-intersecting) polygon, regardless of whether it is convex or non-convex, this angle is called an interior angle(or internal angle) if a point within the angle is in the interior of the polygon.
And if i drew parallel lines, maybe I will draw it straight left and right, it might be a little bit ore obvious so if I assume that these two lines are parallel andI have a transversal here what I'm saying is this angle is going to be the exact same measure as that angle there.
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Find the measurement of angle CAD,so angle CAD… this angle right over here… measure of that angle, let's just call it x, so that I don't have to keep writing the measure of angle CAD and the other thing that might jump out at you is that the measures of the other angles' measures are given here… 50 degrees, 45 degrees and 37 degrees.
And let's say thatthis radius is a length r and that this arc right here is also length r. Then this angle, what's called theta, is equal to one radian. And now it makes sense that they call it a radian?
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So all of these things in green are equivalent and by the same exact argument,this side over here or this angle is going to have the same measure as this angle and that's going to be the same as this angle, because they're opposite, or they're vertical angles. .
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And we know that by corresponding angles congruent of congruent triangles So,we're just saying that this angle is equal to that angle Well, once again these could be alternate interior angles, they look like they could be, this is a transversal and here's two lines here which we're not sure they're parallel but because the alternate interior angles are congruent we know that they are parallel.
Now, we're not talking about perpendicular bisecting the sides, we're talking about bisecting the angles themselves,so we can bisect this angle right over here, my best attempt to draw it- so this angle is going to be equal to that angle, we could bisect this angle right over here, we could bisect- oh, that's- I could do a better version of that so that looks- well, one more try.