Примери за използване на Equation of this line на Английски и техните преводи на Български
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That's the equation of this line right there.
So we need to figure out the equation of this line.
So the equation of this line is seven/ fourx.
So let's see what we have so far for the equation of this line.
The equation of this line is seven/ eightx plus thirteen/ four.
So first we just have to figure out the equation of this line.
The equation of this line is y is equal to negative 5x plus 6.
So what we want to do is figure out the equation of this line.
So if the equation of this line right here is y is equal to mx plus b.
But first, let's also think about what the equation of this line is going to be.
The equation of this line is y is equal to the slope 3/5x, plus the y-intercept, minus 3.
We get b equals one, so that tells us that the equation of this line is y equals x plus one.
Find the equation of this line in point slope form, slope intercept form, standard form.
Well, anyway, we know the slope is negative eleven/ five, so the equation of this line so far is y equals minus eleven/ fivex plus b.
So the equation of this line is y is equal to minus four/ three x and then this y-intercept is minus one/ three.
I know this is extremely messy, but the equation of this line once again, is y equals minus four/ three x minus one/ three.
So the equation of this line, and this one wasn't as clean as the other one, obviously, is-- let me do it in another color for emphasis-- y equals minus eleven/ fivex minus eight/ five.
And if you want to see that this is just one way of expressing the equation of this line-- there are many others, and the one that we're most familiar with is y-intercept form-- this can easily be converted to y-intercept form.
So so far we know the equation of this line is equal to, y is equal to the slope eight/ five x plus b.
Now, if two lines are perpendicular, if the slope of this orange line is m-- so let's say its equation is y is equal to mx plus, let's say it's b 1,so it's some y-intercept-- then the equation of this yellow line, its slope is going to be the negative inverse of this guy.
And this is the equation of the line in point-slope form.
This must satisfy the equation of the line.
Find the equation of a line perpendicular to this line that passes through the point 2 comma 8.
This right here is the equation of a line.
You take x1 into this equation of the line and you're going to get this point right over here.
So this right over here is the point-slope form of the equation that describes this line.
I just know that this is on the point,so this point must satisfy the equation of line B.
Then this line will have angular coefficient of slope 1/4 and therefore its equation, if we return to the normal scale, will be.
So the equation of line B is y is equal to-- its slope is a negative inverse of this character-- so negative 1/2, negative 1/2 x.
Remember, this line represents all of the points that satisfied this equation.