Examples of using Rewrite this in English and their translations into Hebrew
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Colloquial
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Ecclesiastic
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Computer
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Programming
Let me rewrite this.
So, I know this goes without saying,but if either of you tell Leonard you helped me rewrite this paper.
Maybe I can rewrite this part.
You could rewrite, this is just the derivative of psi, with respect to x, inside the function of x, y, is equal to 0.
If I divide-- let me rewrite this.
Let me rewrite this a little bit.
And then we could also rewrite this.
So I could rewrite this as wavelength.
And my question is to you, can I just algebraically rewrite this so it becomes a function of y over x?
Can you rewrite this post with simpler words?
And so if we go back to our ideal gas equation-- PV is equal to nRT--we can just rewrite this by dividing both sides by V, as P is equal to nRT over V.
We could rewrite this as y squared over x squared.
I left a 2r, so we could rewrite this as-- well, actually, I'm running out of space.
You could rewrite this as the magnitude of a sine theta times the magnitude of b in that normal vector direction.
So we could rewrite this as 1 over x 3x plus 10.
We can rewrite this as, well, A is 0, B is minus 2/3.
But this now, I can rewrite this term right here as s plus 1 squared.
So we can rewrite this expression up here-- I will do it in this reddish color-- I was using that, let me do it in the blue color.
You should rewrite this sentence. It doesn't make sense.
We could rewrite this as the roots are going to be equal to minus B over 2A, plus or minus the square root of B squared minus 4AC over 2A.
So I could actually rewrite this reaction where I write all that, and I could have added-- actually, let me do it.
Or we could rewrite this as, the roots r. r is equal to negative 1/2 plus or minus-- well we could rewrite this as i times the square root of 3, or square root of 3i over 2.
If this were true, then we could rewrite this as the partial of psi, with respect to x, plus the partial of psi, with respect to y, times dy, dx, equal to 0.
Or we could just rewrite this as 2 times the unit step function starting at 2, where that's when it becomes non-zero of t times f of t minus 2. f of t minus 2 is this with t being replaced by t minus 2.
So we can rewrite this as mass times the second derivative of x.
So I can rewrite this as the natural log of VB over VA, divided by-- right?
So we could rewrite this as 8 times z plus 2 times minus 1 times z minus 2.
So we can rewrite this as 8 times 2 plus z-- I'm just rearranging it-- times 2 minus z.
And so another way of rewriting this, if we divide both sides by voltage, we get Q/V is equal to 1 over 4K pi area over distance.
Once again we're taking the derivative,so I'm not going to keep rewriting this, but this is the same thing as taking the derivative of the natural log of x times 3x plus ten to the negative 1 power.