Examples of using Mathcal in English and their translations into Ukrainian
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Assume that\(\mathcal{B}\) is a random Banach∗-algebra.
This indicates that the structure of D{\displaystyle{\mathcal{D}}} is extremely complicated.
Regularization can beaccomplished by restricting the hypothesis space H{\displaystyle{\mathcal{H}}}.
Consider the set B{\displaystyle{\mathcal{B}}} of unlabelled binary trees.
Minimize f( x){\displaystyle f(x)\}subject to x∈ C{\displaystyle x\in{\mathcal{C}}}.
F( X, R){\displaystyle{\mathcal{F}}(X,{\mathbb{R}})} is a partially ordered ring.
For a set X{\displaystyle X}, let P X{\displaystyle{\mathcal{P}}X} denote its powerset.
C: X∗→ Σ∗{\displaystyle C:{\mathcal{X\rightarrow\Sigma^{*}} is uniquely decodable if injective.
Incremental Algorithm: Sort the points of P{\displaystyle{\mathcal{P}}} according to x-coordinates.
The triangulations built this wayare referred to as the regular triangulations of P{\displaystyle{\mathcal{P}}}.
A collection of F{\displaystyle{\mathcal{F}}} is called a VC subgraph class if all subgraphs form a VC-class.
Since these singular values tend to 0, R-1{\displaystyle{\mathcal{R}}^{-1}} is unbounded.[9].
Let H{\displaystyle{\mathcal{H}}} be a space of functions f: X→ Y{\displaystyle f: X\to Y} called the hypothesis space.
Consider the(abelian)category of left R{\displaystyle R}-modules M R{\displaystyle{\mathcal{M}}_{R}}.
Thus the singular values of R{\displaystyle{\mathcal{R}}} are 1|| k||{\displaystyle{\sqrt{\frac{1}{||\mathbf{k}.
If, on the other hand,one does have some advance knowledge F{\displaystyle{\mathcal{F}}}.
A modest reasonernever believes B p→ p{\displaystyle{\mathcal{B}}p\to p} unless they believe p{\displaystyle p}.
It is denoted 0(zero)because it is the least element of the poset D{\displaystyle{\mathcal{D}}}.
One way of measuringhow big the function set F{\displaystyle{\mathcal{F}}} is to use the so-called covering numbers.
That is,∃ f: P X→ P Y{\displaystyle\exists_{f}\colon{\mathcal{P}}X\to{\mathcal{P}}Y} is a functor that, for each subset S⊂ X{\displaystyle S\subset X}, gives the subset∃ f S⊂ Y{\displaystyle\exists_{f}S\subset Y} given by.
The canonical parameters for this theory are A= 1{\displaystyle{\mathcal{A}}=1}and B= 0{\displaystyle{\mathcal{B}}=0}.
Some authors require that all the points of P{\displaystyle{\mathcal{P}}} are vertices of its triangulations.[2] In this case, a triangulation of a set of points P{\displaystyle{\mathcal{P}}} in the plane can alternatively be defined as a maximal set of non-crossing edges between points of P{\displaystyle{\mathcal{P}}}.
On the other hand, an explicit representation for φ{\displaystyle\varphi} is not necessary,as long as V{\displaystyle{\mathcal{V}}} is an inner product space.
As you can see, in this case the vector\(\vec V\)and\(\ vec{\ mathcal{ E}}\), and removable NWO, rotated 90 degrees from figure 1.1.
Thus, in a sufficiently rich hypothesis space- or equivalently, for an appropriately chosen kernel- the SVM classifier willconverge to the simplest function(in terms of R{\displaystyle{\mathcal{R}}}) that correctly classifies the data.
Assume that a natural martingale related to$\ mathcal{ M}_{( n)},$ converges almost surely and in the mean to a random variable$W$.
According to the left-hand rule in this casecharges are shifted by vector\(\ vec{\ mathcal{ E}}\), forming a removable NWO, the potential difference\(U\).
In the special case when G 1={∅, Ω}{\displaystyle{\mathcal{ G}}_{ 1}=\{\ emptyset,\Omega\}} and G 2= σ( Y){\displaystyle{\mathcal{ G}}_{ 2}=\ sigma(Y)}, the smoothing law reduces to.
In logic, a logical constant of a language L{\displaystyle{\mathcal{L}}} is a symbol that has the same semantic value under every interpretation of L{\displaystyle{\mathcal{L}}}.
Similarly, the universal quantifier∀ f: P X→ P Y{\displaystyle\forall_{f}\colon{\mathcal{P}}X\to{\mathcal{P}}Y} is a functor that, for each subset S⊂ X{\displaystyle S\subset X}, gives the subset∀ f S⊂ Y{\displaystyle\forall_{f}S\subset Y} given by.