Примери коришћења Mathbf на Енглеском и њихови преводи на Српски
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The symmetry between E{\displaystyle\mathbf{E}}.
E{\displaystyle\mathbf{E}} is the electric field.
And electric field E{\displaystyle\mathbf{E}}.
Then x{\displaystyle\mathbf{x}} is said to be"locally optimal".
Is directly related to the electric field E{\displaystyle\mathbf{E}}.
R{\displaystyler\mathbf{}} is the distance from the current element to the field point.
Where φ is the scalar potential defined by the conservative field F{\displaystyle\mathbf{F}}.
Each x i{\displaystyle\mathbf{x}_{i}} is a p{\displaystyle p}-dimensional real vector.
Any hyperplane can be written as the set of points x{\displaystyle\mathbf{x}} satisfying.
Where w{\displaystyle\mathbf{w}} is the(not necessarily normalized) normal vector to the hyperplane.
We know the classification vector w{\displaystyle\mathbf{w}} in the transformed space satisfies.
As discussed The second step follows from the recursive definition of r d x( n){\displaystyle\mathbf{r}_{dx}(n)}.
It follows that w{\displaystyle\mathbf{w}} can be written as a linear combination of the support vectors.
Note that f{\displaystyle f} is a convex function of w{\displaystyle\mathbf{w}} and b{\displaystyle b}.
If x∈ R n{\displaystyle\mathbf{x}\in\mathbb{R}^{n}} is a vector of independent variables, then the model takes the form.
This is much like Hesse normal form,except that w{\displaystyle\mathbf{w}} is not necessarily a unit vector.
This solution can be checked explicitly by a careful manual evaluation of∇ 2 ϕ E{\displaystyle\nabla^{2}\phi_{\mathbf{E}}}.
In discrete vector spaces,each possible value for x{\displaystyle\mathbf{x}} may be visualized as a vertex in a graph.
Since x{\displaystyle\mathbf{x}} is feasible, we know that A x= b{\displaystyle A\mathbf{x}=\mathbf{b}}.
This can be thought of as anarray of m{\displaystyle m} Hessian matrices, one for each component of f{\displaystyle\mathbf{f}}.
To show that every basic feasible solution is integral,let x{\displaystyle\mathbf{x}} be an arbitrary basic feasible solution.
W T x- b= 1{\displaystyle\mathbf{w}^{T}\mathbf{x} -b=1}(anything on or above this boundary is of one class, with label 1).
The electrostatic potential is simply the special case of this definition where A{\displaystyle\mathbf{A}} is time-invariant.
Moreover, X{\displaystyle\mathbf{X}} is uniformly distributed on[ 0, 1] d{\displaystyle[0,1]^{d}} and m{\displaystyle m} is Lipschitz.
Which is equal to the mean of the Y i{\displaystyle Y_{i}}'s falling in the cells containing x{\displaystyle\mathbf{x}} in the forest.
Let x 0={\displaystyle\mathbf{x}_{0}=} be the elements corresponding to the basis columns for the basic solution x{\displaystyle\mathbf{x}}.
This function is zero if the constraint in(1) is satisfied, in other words,if x i{\displaystyle\mathbf{x}_{i}} lies on the correct side of the margin.
The parameter b‖ w‖{\displaystyle{\tfrac{b}{\|\mathbf{w}\|}}} determines the offset of the hyperplane from the origin along the normal vector w{\displaystyle\mathbf{w}}.
At each iteration,hill climbing will adjust a single element in x{\displaystyle\mathbf{x}} and determine whether the change improves the value of f( x){\displaystyle f(\mathbf{x})}.
The missing values(aka latent variables)Z{\displaystyle\mathbf{Z}} are discrete, drawn from a fixed number of values, and with one latent variable per observed unit.